21

If both 117 and 88 are factors of the given product A x 47 x 64 x 767, then what is the smallest possible value of 'A'?

Answer : Option B

Explanation:

In the given product,

A x 45 x 64 x 767117 x 88

A x 5 x 9 x 8 x 8 x 13 x 5913 x 9 x 8 x 11

A x 5 x 9 x 8 x 8 x 13 x 5913 x 9 x 8 x 11

A x 5 x 8 x 5911

In order to divide numerator with denominator, the A value must be 11 

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22

If the number 347A25B is divisible by 15, (in decimal notation, where A, B are digits > 0), then what is the minimum value of A + B?

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23

If a number 774958A95B is to be divisible by 4 and 9, the value of A and B respectively will be:

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24

A natural number has exactly 10 divisors including 1 and itself. How many distinct prime factors can this natural number can have?

Answer : Option B

Explanation:

is either 1 or 2 .
example if the no is 512 . then the divisors of this no. are
1,2,4,8,16,32,64,128,256,512;
so only one prime factors are there 2;
if the no is 48 the divisors are
1,2,3,4,6,8,12,16,24,48;
so the prime factors are 2,3;

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25

For Rs 600 Mr. Karan can buy a maximum of 24 cups of tea and for Rs 1000 he can buy a maximum of 15 cups of coffee. He has Rs 2200 in his pocket and purchase 8 cups of tea. What is the maximum number of cups of coffee Mr. Karan can purchase with the remaining money?

Answer : Option D

Explanation:

 15 coffee=> 1000/15=66.67

so one cup could be rs 66 max,now possible rs values of a cup66*15=990rs (given in ques, can buy only 15 cups max)65*15=975rs (given in ques, can buy only 15 cups max)

{since if we buy 16 cups each of 65rs then we get 65*16=1040 > 1000}

so 65 is also possible value as it is not violating the question constraint.

same as above64*15= 960rs (but 64*16 > 1000)

63*15= 945rs (but 63*16 > 1000)

62*15= 930rs (but 62*16 < 1000)(so one can buy 16 cup each of 62rs in rs 1000 which is not given in the question i mean one can buy only 15 cup in 1000rs)

so 62 is not possible.Now we have 63,64,65,66 possible values… as we want to maximize the no. of cups so we have to minimize the cost which is 63.now 2000/63=31.***

so the answer is 31.

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26

The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. How many such numbers are there?

Answer : Option D

Explanation:

 Let the digits be x and y. then the number is 10x+y

given: (10x+y)^2/[(10x+y)/2]=2(10x+y).

[2(10x+y)+36]/2=10y+x

or, 10x+y+18=10y+x

or, 9y=9x+18

or, y=x+2

therefore, 10x+y=13,24,35,46,57,68,79

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27

A two digit number is equal to the sum of its tens digit and the square of its units digit. What is the value when the number is added to the sum of its digits? 

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28

What is the remainder when (5555)2222 + (2222)5555 is divided by 7?

Answer : Option A

Explanation:

 

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29

Find the units digit in the given expression 13 + 23 + 33 + 43 ................+ 983+ 993

Answer : Option D

Explanation:

 

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30

A six digit number 64A998 is divisible by 6. How many values of A are possible?

Answer : Option B

Explanation:

Since the number is ending with an even digit, the number is divisible by 2. Now in order to divisible by 6, it has to be divisible by 3 also.

To divisible by 3 --- the sum of the digits of the number3

The sum of the digits 6 + 4 + A + 9 + 9 + 8 = 36 + A

36 + A has to be divisible by 3.

So, A can take values 0, 3, 6 and 9.

Hence the number of values A can take = 4

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