31

There are 11 alphabets A, H, I, M, O, T, U, V, W, X, Y. They are called symmetrical alphabets. The remaining alphabets are known as asymmetrical alphabets. How many three-lettered words can be formed such that at least one symmetrical letter is there?

Answer : Option D

Explanation:

There are 11 symmetrical alphabets A, H, I, M, O, T, U, V, W, X, Y and number of asymmetrical letters will be 15

Total number possible of words = 26 × 26 × 26 = 17576

Number of words without any symmetrical letters = 15 × 15 × 15 = 3375

Number of words with at least one symmetrical letter

= 17576 − 3375 = 14201

Hence, option 4. 

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Ramanjaneyulu s

Thank you

Sudhakar

Thans For Giving Solution

Pavan Jaiswal

This Solution is very simple thanks for giving video solution.its very eay for understood.

Ramanjaneyulu s

Thank you

Sudhakar

Thans For Giving Solution

Pavan Jaiswal

This Solution is very simple thanks for giving video solution.its very eay for understood.

32

How many 4 digit numbers contain a digit 2?

Answer : Option D

Explanation:

 First all the four digit numbers using digits 0 to 9

__9__  x  _10__ x  _10_  x  _10_   = 9000 numbers

 Second all the four digit numbers using digits 0 to 9 which do not contain digit 2

__8__  x  _9__ x  _9_  x  _9_   = 5832 numbers

 

Now Subtract

9000 - 5832 = 3168

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Ramanjaneyulu s

Thank you

Sudhakar

Thans For Giving Solution

Pavan Jaiswal

This Solution is very simple thanks for giving video solution.its very eay for understood.

Ramanjaneyulu s

Thank you

Sudhakar

Thans For Giving Solution

Pavan Jaiswal

This Solution is very simple thanks for giving video solution.its very eay for understood.